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1 有一圓盤離合器,外徑為12cm,內徑為8cm,若μ=0.3,軸向壓力為196N,若轉速為600rpm,則其傳遞的功率為
A 0.25PS
B 1PS
C 2.5PS
D 2PS

Dm=(D1+D2)/2=(12+8)/2=10cm=0.1m

T=(1/2)×0.3×(196/9.8)×0.1 =0.3(kg-m)

P=T×W=0.3×(2π×600/60)×1/75=0.25(PS)