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    14.素養(4)
1 如圖所示電路,電流 I 為何? 111 統測
A 1mA
B 3mA
C 5mA
D 6mA

假設左邊節點接地,右邊節點電壓為 V,及電流方向如下

5m = V10k + V - (-10)20k (兩邊同乘 20k)

100 = 2V+ V +10

3V = 90 ⟹ V=30V

I = 3010k = 3 mA