Positive SSL
1 一運算放大器的Ad=100,Ac=0.5,兩個輸入分別是V+(t)=0.01cos(2π400t)+0.2cos(2π60t),V-(t)=-0.01cos(2π400t)+0.2cos(2π60t),求運算放大器的輸出Vo(t)
A 2cos(2π400t)+0.1cos(2π60t)
B 1cos(2π400t)+0.2cos(2π60t)
C 2cos(2π400t)+0.2cos(2π60t)
D 4cos(2π400t)+0.1cos(2π60t)

Vd = `V_+ - V_-` = 0.02cos(2π400t)

Vc = `(V_++ V_-)/2` = 0.2cos(2π60t)

Vo =Ad.Vd + Ac.Vc

= 100.0.02cos(2π400t)+0.5.0.2cos(2π60t)

= 2cos(2π400t)+0.1cos(2π60t)