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1 如圖所示,為矽二極體,V=20V,R1=3.3kΩ,R2=5.6kΩ,求I2約為何值?
A 2.7mA
B 3.1mA
C 3mA
D 3.9mA

矽二極體導通0.7V壓降,將原電路轉換成如圖電路

流過 5.6kΩ 電阻電流 `I_(5.6k)` = `(20-0.7-0.7)/(5.6k)` = 3.32mA

流過 3.3kΩ 電阻電流 `I_(3.3k)` = `(0.7)/(3.3k)` = 0.21mA

`I_2` = 3.32-0.21 = 3.11mA