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1 如圖所示,求F=500N之力在x方向的分力為
A 196.4N
B 250N
C 306.4N
D 436.4N

如圖所示,x 方向的分力

500×cos(30°+α)

500×cos30°cosα-sin30°sinα)

cosα=4/5=0.8,sinα=3/5=0.6

cos30°=`sqrt(3)/2`=0.866,sin30°=1/2=0.5

500×0.866×0.8-0.5×0.6)

500×(0.6928-0.3)

500×0.3928

=196.4(N)